Maths Library

Long Division: Grade 6 math

Master formal long division algorithms dividing multi-digit numbers by two-digit divisors. Practice reinforces structured working, estimation, and handling remainders.

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What this covers

Long Division is taught in Grade 6 (age 11 to 12) as a topic to introduce. It sits in the Number strand.

Worked example

Calculate 78223

  1. 23 into 78 goes 3 times (3 × 23 = 69)
  2. 78 - 69 = 9; bring down 2 to make 92
  3. 23 into 92 goes exactly 4 times (4 × 23 = 92)
  4. 92 - 92 = 0; quotient is 34

Answer: 34

Difficulty scale

The sheet generator offers five difficulty settings for this topic.

  1. 3-digit dividend divided by teen divisor (11-19), exact answers
  2. 3-digit dividend divided by any 2-digit divisor, exact answers
  3. 4-digit dividend divided by 2-digit divisor, exact answers
  4. 4-digit dividend divided by 2-digit divisor, answers with integer remainders
  5. 4-digit dividend divided by 2-digit divisor, expressing answers as decimals

Common mistakes

  • Misestimating the quotient digit, leading to negative subtractions or remainders larger than the divisor
  • Bringing down multiple digits at once without recording a zero in the quotient

Curriculum links

Indicative matches to Common Core State Standards. Check wording and codes against the official document.

  • 6.NS.B.2 Fluently divide multi-digit whole numbers using the standard long division algorithm.

Sample sheet and answers

Six questions at the level's usual difficulty. Open the editor to change, add or regenerate any of them.

Long Division

Grade 6 math

Qs
6
Marks
24
NameDateScore / 24
1.
1089 ÷ 12 = ? Give the quotient and remainder.
[4]
2.
2506 ÷ 20 = ? Give the quotient and remainder.
[4]
3.
2315 ÷ 28 = ? Give the quotient and remainder.
[4]
4.
5331 ÷ 23 = ? Give the quotient and remainder.
[4]
5.
5211 ÷ 22 = ? Give the quotient and remainder.
[4]
6.
3913 ÷ 21 = ? Give the quotient and remainder.
[4]

Answer key

  1. 90 remainder 912 × 90 = 1080; 1089 − 1080 = 9
  2. 125 remainder 620 × 125 = 2500; 2506 − 2500 = 6
  3. 82 remainder 1928 × 82 = 2296; 2315 − 2296 = 19
  4. 231 remainder 1823 × 231 = 5313; 5331 − 5313 = 18
  5. 236 remainder 1922 × 236 = 5192; 5211 − 5192 = 19
  6. 186 remainder 721 × 186 = 3906; 3913 − 3906 = 7